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How do you find the derivative of #y=ln(cosx^2)#?

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Nov 1, 2016

#y = ln(cosx^2)#
#e^y=cos(x^2)#
#y'e^y=-2xsin(x^2)#
#y' = (-2xsin(x^2))/e^y#

but #e^y =cos(x^2)#

so

#y' = (-2xsin(x^2))/cos(x^2) #

#y' = -2xtan(x^2)#

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