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How do you find the derivative of #y = [e^(-1) + e^(t)]^3#?

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May 15, 2015

The answer is : #3(e^(-1) + e^t)^2*e^t #

#dot y = dot [(e^(-1) + e^t)^3] = 3(e^(-1) + e^t)^2*dot ((e^(-1)+e^t))#

#= 3(e^(-1) + e^t)^2*e^t #

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