How do you find the derivative of #y=cos 3x#?

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How do you find the derivative of #y=cos 3x#?

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Answer 1 · 2015-02-07T12:58:30

You can use the Chain Rule: first you derive the #cos# as it is (without changing its argument) and then multiply by the derivative of the argument, #3x#.

So you get:

#y'=-sin(3x)*3=-3sin(3x)#

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How do you find the derivative of #y=cos 3x#?

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