How do you find the derivative of #y=arcsin(5x+5)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Shwetank Mauria May 14, 2016 #(dy)/(dx)=5/(sqrt(1-(5x+5)^2)# Explanation: As #y-arcsin(5x+5)#, #siny=5x+5# Taking derivative of both sides #cosy(dy)/(dx)=5# #(dy)/(dx)=5/cosy=5/(sqrt(1-sin^2y)# = #5/(sqrt(1-(5x+5)^2)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1452 views around the world You can reuse this answer Creative Commons License