How do you find the derivative of $y = \frac{3}{cos 2 x^{2}}$ $y = 3 / (cos2x^2)$ ?

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Answer 1 · 2017-04-14T20:17:19

$\frac{d y}{d x} = 12 x sec (2 x^{2}) tan (2 x^{2})$ $dy/dx=12xsec(2x^2)tan(2x^2)$

Rewrite the problem as:

$y = 3 (sec (2 x^{2}))$ $y=3(sec(2x^2))$

Now take the derivative. You have to use chain rule for $sec (2 x^{2})$ $sec(2x^2)$

$dy/dx=3(sec(2x^2))tan(2x^2)(2x^2)'$

$dy/dx=12xsec(2x^2)tan(2x^2)$

How do you find the derivative of y = 3 / (cos2x^2)y=3cos2x2y = 3 / (cos2x^2)?