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How do you find the derivative of #y = 3 / (cos2x^2)#?

1 Answer

Apr 14, 2017

#dy/dx=12xsec(2x^2)tan(2x^2)#

Explanation:

Rewrite the problem as:

#y=3(sec(2x^2))#

Now take the derivative. You have to use chain rule for #sec(2x^2)#

#dy/dx=3(sec(2x^2))tan(2x^2)(2x^2)'#

#dy/dx=12xsec(2x^2)tan(2x^2)#

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