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How do you find the derivative of #y=-(2x+3+4x^-1)^-1#?

1 Answer

sankarankalyanam

Oct 23, 2017

#y’ = (2-(4/x^2))/(2x + 3 + (4/x))^2#

Explanation:

#y= -(2x + 3 + 4x^-1)^-1#

#y’ = (- (-1) (2x + 3 + x^-1)^-2) * (2 + 4 (-1)x^-2)#

# y’ =(1/ (2x + 3 + (4/x))^2) * (2 - (4/x^2))#

#y’ = (2-(4/x^2))/(2x + 3 + (4/x))^2#

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