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How do you find the derivative of #xsqrt(2x - 3)#?

1 Answer

Apr 1, 2016

#f'(x)= (3(x-1))/sqrt(2x-3)#

Explanation:

Using product rule #f=uv => f'=u'v+uv'#, we have:

#f'(x)= (xsqrt(2x-3))'=1*sqrt(2x-3)+x*1/(2sqrt(2x-3))*2#

#f'(x)= sqrt(2x-3)+x/sqrt(2x-3)#

#f'(x)= (3x-3)/sqrt(2x-3)#

#f'(x)= (3(x-1))/sqrt(2x-3)#

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