How do you find the derivative of $x*sqrt(x+1)$ ?

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Answer 1 · 2016-06-03T14:13:16

$d/(d x)(x*sqrt(x+1))=(3x+2)/(2*sqrt(x+1))$

$d/(d x)(x*sqrt(x+1))=?$

$d/(d x)(x*sqrt(x+1))=x^'*sqrt(x+1)+(sqrt(x+1))^'*x$

$d/(d x)(x*sqrt(x+1))=1*sqrt(x+1)+1/(2*sqrt(x+1))*x$

$d/(d x)(x*sqrt(x+1))=sqrt(x+1)+x/(2*sqrt(x+1))$

$d/(d x)(x*sqrt(x+1))=[(2*sqrt(x+1)*sqrt(x+1))+x]/(2*sqrt(x+1))$

$d/(d x)(x*sqrt(x+1))=(2x+2+x)/(2*sqrt(x+1))$

$d/(d x)(x*sqrt(x+1))=(3x+2)/(2*sqrt(x+1))$

How do you find the derivative of x*sqrt(x+1)x*sqrt(x+1)?