How do you find the derivative of #(x^3+1)^2#?
1 Answer
Jan 23, 2016
Explanation:
Use the chain rule, which states that
#d/dx[(x^3+1)^2]=d/dx[x^3+1]*2(x^3+1)#
#d/dx[(x^3+1)^2]=3x^2*2(x^3+1)#
#d/dx[(x^3+1)^2]=6x^2(x^3+1)#