How do you find the derivative of $(x^3+1)^2$ ?

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Answer 1 · 2016-01-23T04:56:27

$d/dx[(x^3+1)^2]=6x^2(x^3+1)$

Use the chain rule, which states that $d/dx[u^2]=u'*2u$ . Here, we know that $u=x^3+1$ , so

$d/dx[(x^3+1)^2]=d/dx[x^3+1]*2(x^3+1)$

$d/dx[(x^3+1)^2]=3x^2*2(x^3+1)$

$d/dx[(x^3+1)^2]=6x^2(x^3+1)$

How do you find the derivative of (x^3+1)^2(x^3+1)^2?