# How do you find the derivative of (x^2-1)^3?

I found: $6 x {\left({x}^{2} - 1\right)}^{2}$
I would use the Chain Rule to derive ${\left(\right)}^{3}$ first and then multiply times the derivative of the argument and get:
$y ' = 3 {\left({x}^{2} - 1\right)}^{2} \cdot 2 x = 6 x {\left({x}^{2} - 1\right)}^{2}$