How do you find the derivative of #v=4(2x^2-x+3)^-2#?
1 Answer
Apr 14, 2017
Explanation:
differentiate using the
#color(blue)"chain rule"#
#"Given " f(x)=g(h(x))" then"#
#• f'(x)=g'(h(x))xxh'(x)#
#rArr(dv)/dx=-8(2x^2-x+3)^-3xxd/dx(2x^2-x+3)#
#color(white)(rArrdv/dx)=-8(4x-1)(2x^2-x+3)^-3#
