How do you find the derivative of #tan^2x#?

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How do you find the derivative of #tan^2x#?

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Answer 1 · 2015-08-16T11:42:54

I found: #y'=2tan(x)/cos^2(x)#

Explanation:

You can use the Chain Rule to deal first with the #()^2# and then with #tan#. Remember that the derivatve of #tan(x)# is #1/cos^2(x)#.
So you get:
#y'=color(red)(2*tan(x))*color(blue)(1/cos^2(x))=2tan(x)/cos^2(x)#

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How do you find the derivative of #tan^2x#?

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