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How do you find the derivative of #sqrt (x^2 +1)#?

1 Answer

Mar 10, 2016

#x/sqrt(x^2 + 1)#

Explanation:

#f(x) = sqrt(x^2 + 1)#
#f(x) = (x^2 + 1)^(1/2)#

#f'(x) = 1/2(x^2 + 1)^(-1/2) . (2x + 0)#
#f'(x) = (2x)/(2 sqrt(x^2 + 1))#

#f'(x) = x/sqrt(x^2 + 1)#

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