# How do you find the derivative of sqrt x^2?

$\frac{d}{\mathrm{dx}} \left[{\sqrt{x}}^{2}\right] = \frac{d}{\mathrm{dx}} \left[x\right] = 1$
${\sqrt{x}}^{2} = {x}^{0.5 \times 2} = {x}^{1} = x$
$\frac{d}{\mathrm{dx}} \left[x\right] = 1$