How do you find the derivative of #sqrt(4+x^2)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Bill K. May 21, 2015 Use the Power Rule and Chain Rule: #d/dx((4+x^2)^{1/2})=\frac{1}{2}(4+x^2)^{-1/2}\cdot 2x=x/sqrt(4+x^2)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1419 views around the world You can reuse this answer Creative Commons License