How do you find the derivative of #sinh^79(x)#?
1 Answer
Mar 2, 2016
Explanation:
According to the chain rule,
#d/dx(u^79)=79u^78*u'#
So:
#d/dx(sinh^79(x))=79sinh^78(x)*d/dx(sinh(x))#
#=79sinh^78(x)cosh(x)#
