How do you find the derivative of sec^2(x)? Calculus Differentiating Trigonometric Functions Derivatives of y=sec(x), y=cot(x), y= csc(x) 1 Answer Bill K. Jul 27, 2015 2sec^{2}(x)tan(x) Explanation: Use the Chain Rule: d/dx(sec^{2}(x))=2sec(x)*d/dx(sec(x)) =2sec(x)*sec(x)tan(x)=2sec^{2}(x)tan(x) Answer link Related questions What is Derivatives of y=sec(x) ? What is the Derivative of y=sec(x^2)? What is the Derivative of y=x sec(kx)? What is the Derivative of y=sec ^ 2(x)? What is the derivative of y=4 sec ^2(x)? What is the derivative of y=ln(sec(x)+tan(x))? What is the derivative of y=sec^2(x)? What is the derivative of y=sec^2(x) + tan^2(x)? What is the derivative of y=sec^3(x)? What is the derivative of y=sec(x) tan(x)? See all questions in Derivatives of y=sec(x), y=cot(x), y= csc(x) Impact of this question 1578 views around the world You can reuse this answer Creative Commons License