How do you find the derivative of #S(r)=9r^2+3tanr#?

1 Answer
Jim G.
Dec 29, 2016

#S'(r)=18r+3sec^2r#

Explanation:

differentiate the first term using the #color(blue)"power rule"# and use the #color(blue)"standard derivative for tan"#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx(ax^n)=nax^(n-1))color(white)(2/2)|)))" power rule"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx(tanx)=sec^2x)color(white)(2/2)|)))#

#S(r)=9r^2+3tanr#

#rArrS'(r)=18r+3sec^2r#

Related questions
See all questions in Derivatives of y=sec(x), y=cot(x), y= csc(x)
Impact of this question
1814 views around the world
You can reuse this answer
Creative Commons License