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How do you find the derivative of #r(x)= (0.3x^2-4.2x+9.2)^1.5#?

1 Answer

Mar 15, 2016

#r'(x)= (0.9x-6.3)sqrt(0.3x^2-4.2x+9.2)#

Explanation:

#r(x)= (0.3x^2-4.2x+9.2)^1.5#

#r(x)= (0.3x^2-4.2x+9.2)^(3/2)#

#r'(x)= 3/2(0.3x^2-4.2x+9.2)^(1/2) * (0.3x^2-4.2x+9.2)'#

#r'(x)= 3/2(0.3x^2-4.2x+9.2)^(1/2) * (0.6x-4.2)#

#r'(x)= (0.9x-6.3)sqrt(0.3x^2-4.2x+9.2)#

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