How do you find the derivative of #r= 2theta sqrt(sec theta)# using the chain rule?

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How do you find the derivative of #r= 2theta sqrt(sec theta)# using the chain rule?

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Answer 1 · 2017-09-16T12:10:31

#(dr)/(d theta)=sqrtsectheta (2+thetatantheta)#

Explanation:

#r=2thetasqrtsectheta#
Differentiating both sides with respect to #theta# we get
#(dr)/(d theta)=2sqrtsectheta + 2theta×1/(2sqrtsectheta)secthetatantheta#
#=2sqrtsectheta+thetasqrtsecthetatantheta#
#=sqrtsectheta (2+thetatantheta)#

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How do you find the derivative of #r= 2theta sqrt(sec theta)# using the chain rule?

1 Answer

Explanation:

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