How do you find the derivative of # lnx / x#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Alan N. Aug 23, 2016 #(1-lnx)/x^2# Explanation: #f(x) = lnx/x# #f'(x) = (x*1/x - lnx*1)/x^2# (Quotient rule and standard differential) #= (1-lnx)/x^2# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1161 views around the world You can reuse this answer Creative Commons License