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How do you find the derivative of # (ln(x^2))/x^2#?

1 Answer

Vinícius Ferraz

Jul 13, 2017

#2 * frac{1 - ln x^2}{x^3}#

Explanation:

#D_x ln(x^2)/x^2 = frac{x^2 D_x ln x^2 - ln x^2 D_x x^2}{x^4}#

# = frac{x^2 1/x^2 D_x x^2 - 2x ln x^2}{x^4}#

# = frac{2x - 2x ln x^2}{x^4}#

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