# How do you find the derivative of #ln(x^2+1)#?

##### 1 Answer

# d/dx ln(x^2+1)= (2x)/(x^2+1) #

#### Explanation:

If you are studying maths, then you should learn the Chain Rule for Differentiation, and practice how to use it:

If

# y=f(x) # then# f'(x)=dy/dx=dy/(du)(du)/dx #

I was taught to remember that the differential can be treated like a fraction and that the "

# dy/dx = dy/(dv)(dv)/(du)(du)/dx # etc, or# (dy/dx = dy/color(red)cancel(dv)color(red)cancel(dv)/color(blue)cancel(du)color(blue)cancel(du)/dx) #

So with

Using

# dy/dx = (1/u)(2x) #

# :. dy/dx = (2x)/(x^2+1) #