# How do you find the derivative of  ln(x+1)?

Using chain rule, which states that $\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{\mathrm{dy}}{\mathrm{du}} \frac{\mathrm{du}}{\mathrm{dx}}$
Here, $u = x + 1$, so
$\frac{\mathrm{dy}}{\mathrm{dx}} = \left(\frac{1}{u}\right) \left(1\right) = \frac{1}{u} = \frac{1}{x + 1}$