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How do you find the derivative of #ln sqrt (x^2-4)#?

1 Answer

Mar 8, 2016

#d/dx (ln sqrt (x^2-4)) = x/(x^2-4)#

Explanation:

#ln sqrt (x^2-4) = 1/2 ln (x^2-4)#

Hence:

#[ln sqrt (x^2-4)]^' = [1/2 ln (x^2-4)]^'#
#=1/2 * (x^2-4)^'/(x^2-4) =1/2 * (2x)/(x^2-4) = x/(x^2-4)#

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