Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you find the derivative of #ln sqrt (x^2-4)#?

1 Answer

Mar 8, 2016

#d/dx (ln sqrt (x^2-4)) = x/(x^2-4)#

Explanation:

#ln sqrt (x^2-4) = 1/2 ln (x^2-4)#

Hence:

#[ln sqrt (x^2-4)]^' = [1/2 ln (x^2-4)]^'#
#=1/2 * (x^2-4)^'/(x^2-4) =1/2 * (2x)/(x^2-4) = x/(x^2-4)#

Related questions

See all questions in Chain Rule

Impact of this question

9197 views around the world

You can reuse this answer
Creative Commons License