How do you find the derivative of #ln(e^(4x)+3x)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer A. S. Adikesavan Apr 22, 2016 #(4 e^(4x)+3)/( e^(4x)+3x)# Explanation: y = log u, where u = #e^(4x)+3# #y'=(dy)/(du) u'# #= 1/u(4e^(4x)+3)# #=(4 e^(4x)+3)/( e^(4x)+3x)# Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 1124 views around the world You can reuse this answer Creative Commons License