How do you find the derivative of #g(x)=3(2-5x)^6#? Calculus Basic Differentiation Rules Chain Rule 1 Answer marfre Mar 26, 2017 #g'(x) = -90(2-5x)^5# Explanation: Use the differentiation power rule #(u^n)' = n u^(n-1) u'# Note: #d/(du) (3u) = 3# Let #u = 2-5x, u' = -5# #g'(x) = 3*6(2-5x)^5 (-5)# #g'(x) = -90(2-5x)^5# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1153 views around the world You can reuse this answer Creative Commons License