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How do you find the derivative of #g(t) = 1/t^(1/2)#?

1 Answer

Mar 1, 2017

#g'(t) = -1/(2t^(3/2))#

Explanation:

#g(t) = 1/t^(1/2) = t^(-1/2)#

Applying the power rule:

#g'(t) = -1/2 t^((-1/2-1)) = -1/2 t^(-3/2)#

#= -1/(2t^(3/2))#

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