How do you find the derivative of #f(x)=-xe^x + 2#?
1 Answer
Mar 12, 2017
Explanation:
differentiate
#xe^x# using the#color(blue)"product rule"#
#"Given "y=g(x).h(x)" then"#
#• dy/dx=g(x)h'(x)+h(x)g'(x)#
#"here "g(x)=xrArrg'(x)=1#
#"and "h(x)=e^xrArrh'(x)=e^x#
#rArrf(x)=-xe^x+2#
#rArrf'(x)=-(x.e^x+e^x)+0=-xe^x-e^x#
#color(white)(rArrf'(x))=-e^x(x+1)#
