How do you find the derivative of #f(x)=x^2-(1/x)#?

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Answer 1 · 2017-02-19T11:04:50

#f'(x)=2x+1/x^2#

The derivative of a sum is the sum of the derivatives and the terms can be considered in the form

#x^n#

whose derivative is

#n*x^(n-1)#

Let's rewrite:

#f(x)=x^2-x^(-1)#

Then

#f'(x)=2x-(-1)x^(-2)=2x+1/x^2#