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How do you find the derivative of #f(x)=(8x^2-6)^-1#?

1 Answer

Shwetank Mauria

Jun 16, 2016

#(df)/(dx)=-(16x)/(8x^2-6)^2#

Explanation:

We use the chain rule here.

As #f(x)=(8x^2-6)^(-1)#

#(df)/(dx)=-1xx(8x^2-6)^(-1-1)xx(16x)# or

= #-1/(8x^2-6)^2xx(16x)#

= #-(16x)/(8x^2-6)^2#

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