How do you find the derivative of ${cos (1 - 2 x)}^{2}$ $cos(1-2x)^2$ ?

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How do you find the derivative of ${cos (1 - 2 x)}^{2}$ $cos(1-2x)^2$ ?

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Answer 1 · 2018-05-11T15:32:34

$4 (1 - 2 x) {sin (1 - 2 x)}^{2}$ $4(1-2x)sin(1-2x)^2$

Explanation:

$differentiate using the chain rule$ $"differentiate using the "color(blue)"chain rule"$

$given y = f (g (x)) then$ $"given "y=f(g(x))" then"$

$dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"$

$rArrd/dx(cos(1-2x)^2)$

$=-sin(1-2x)^2xxd/dx((1-2x)^2)$

$=-sin(1-2x)^2xx2(1-2x)xxd/dx(1-2x)$

$=-sin(1-2x)^2xx2(1-2x)xx-2$

$=4(1-2x)sin(1-2x)^2$

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How do you find the derivative of ${cos (1 - 2 x)}^{2}$ $cos(1-2x)^2$ ?

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How do you find the derivative of ${cos (1 - 2 x)}^{2}$ $cos(1-2x)^2$ ?