How do you find the derivative of #C=7/4x+8x²#?

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Answer 1 · 2018-07-21T15:27:59

#{dC}/dx=7/4+16x#

Given function:

#C=7/4x+8x^2#

differentiating above function #C# w.r.t. #x# as follows

#{dC}/dx=d/dx(7/4x+8x^2)#

#=7/4d/dx(x)+8d/dx(x^2)#

#=7/4(1)+8(2x)#

#=7/4+16x#

Answer 2 · 2018-07-21T16:09:27

#16x+7/4#

We essentially are trying to find

#d/dx (8x^2+7/4x)#

We can use the Power Rule: The exponent is multiplied by the coefficient, and the power is decremented by one. We get

#C'=16x+7/4#

Hope this helps!