How do you find the derivative of # 1/[16x+3]^2# using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer mason m Nov 21, 2015 #f'(x)=-32/(16x+3)^3# Explanation: #f'(x)=(16x+3)^-2# According to the Chain Rule, #f'(x)=-2(16x+3)^-3*stackrel"This term = 16."overbrace(d/dx[16x+3]# #f'(x)=-32/(16x+3)^3# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1449 views around the world You can reuse this answer Creative Commons License