How do you find the derivative for #g(x)= 3tan4x#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Guilherme N. May 23, 2015 The derivative of #tan(u)# is given by #u'sec^2u#. As #u=4x#, then #u'=4# #(dy)/(dx)=3(4sec^2(4x))=12sec^2(4x)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 5784 views around the world You can reuse this answer Creative Commons License