How do you find slope and y-intercept of y + 5 = 6x?

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Answer 1 · 2016-05-08T08:51:51

#y_("intercept") =5#

#"gradient is "6 =># for every 1 along the graph goes up 6

This is a variant on the standard equation for straight line graph which is: #y=mx+c#

So #y+5=6x" becomes "y+c=mx#

Where #m# is the gradient #=> mx->6x =>" gradient is "6#

and where #y_("intercept")-> c =5#

Answer 2 · 2016-05-08T08:58:40

Equations of straight lines changed into the form #y= mx + c# will give you the slope #m# and the y-intercept #c# immediately.
#m = 6# and #c = -5#

Write the equation with just #y# on one side.
#y = 6x -5#

That's it!
Now you have the slope #(-6)# and the y-intercept #(5)#

Take note that in the term #6x#, only the number represents the slope. Do not make the mistake of using #6x# as the slope.

The slope of a line is a number - often a fraction.

#m= "change in the y-values"/"change in the x-values"#

In Geography this is given as

#"gradient"= "vertical displacement"/"horizontal displacement"#