How do you write #-5x+12=20# in slope intercept form?

Question

6539 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-11-28T20:57:52

#-5x+12=20#

by subtracting #12#,

#=> -5x=8#

by dividing by #-5#,

#=> x=-8/5#,

which is a vertical line, whose slope is undefined, so it cannot be written in Slope-Intercept Form.

I hope that this was helpful.