How do you find nth term rule for r=-2 and $a_{1} = 6$ $a_1=6$ ?

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Answer 1 · 2016-07-18T22:39:15

$T_{n} = 6 \times - 2^{n - 1}$ $T_n = 6 xx -2^(n-1)$

If there is a common ratio, r, it must be a G P

In a GP, the general term is $T_{n} = a r^{n - 1}$ $T_n= ar^(n-1)$

$T_{n} = 6 \times - 2^{n - 1}$ $T_n = 6 xx -2^(n-1)$

How do you find nth term rule for r=-2 and a_1=6a1=6a_1=6?