How do you find five ordered pairs of #4x - y = 8#?

1 Answer
Alan P.
Oct 20, 2017

See below for method and sample pairs

Explanation:

If #4x-y=8#
then #y=4x-8#

Choosing 5 arbitrary values for #x#
#color(white)("XXX")#(I chose {0,1,2,3,4})
and solve for corresponding values of #y#

#{: (ul(x),ul(y=4x-8)), (0,-8), (1,-4), (2,color(white)("x")0), (3,color(white)("x")4), (4,color(white)("x")8) :}#

would give the 5 pairs:
#(0,-8), (1,-4),(2,0),(3,4),(4,8)#

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