How do you find equations of the lines passing through (1,3 ) with slope -2/3?

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Answer 1 · 2016-07-01T14:36:54

standard form #3y-2x-11=0#

To find the equation of the line passing through #(1,3) with a slope of #-2/3#

We will use the point-slope formula #(y-y_1) = m(x-x_1)#

Where #m# is the slope and #(x_1,Y_1)#are the coordinates of the point on the line.

#m=-2/3#
#x_1=1#
#y_1=3#

#(y-3) = -2/3(x-1)#

#y-3=-2/3x+2/3#

#ycancel(-3) cancel(+3)=-2/3x+2/3 +3#

#y=-2/3x+2/3 +9/3#

#y=-2/3x+(11)/3#

#(3)y=-(2/cancel3x+(11)/cancel3)cancel3#

#3y=2x+11#

#3y-2x-11=cancel(2x)cancel(+11)cancel(-2x)cancel(-11)#

#3y-2x-11=0#