How do you find all points of inflection given $y=-(x+2)^(2/3)$ ?

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Answer 1 · 2016-12-14T04:51:46

There are no points of inflection.

$y'' = 2/(9(x+2)^(4/3))$ which is always positive.

The concavity does not change, so there are no inflection points.

How do you find all points of inflection given y=-(x+2)^(2/3)y=-(x+2)^(2/3)?