# How do you find a standard form equation for the line with (-5, -16) with a slope of 2?

##### 2 Answers

#### Explanation:

First, we use the point-slope formula to write an equation for the line:

The point-slope formula states:

Where

Now we can transform to the standard form.

The standard form of a linear equation is:

where, if at all possible,

#### Explanation:

The

#color(blue)"standard form equation "# of a line is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(ax+by+c=0)color(white)(2/2)|)))# Before this, we can write the equation in

#color(blue)"point-slope form"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#

where m represents the slope and# (x_1,y_1)" a point on the line"# here

#m=2" and " (x_1,y_1)=(-5,-16)#

#rArry-(-16)=2(x-(-5))#

#rArry+16=2(x+5)#

#rArry+16=2x+10larrcolor(red)" in point-slope form"# Rearranging in standard form.

#rArr2x-y-6=0larrcolor(red)" in standard form"#