How do you factor $x^{3} - 2 x^{2} + 3 x - 6 = 0$ $x^3 - 2x^2 + 3x -6 = 0$ by grouping?

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How do you factor $x^{3} - 2 x^{2} + 3 x - 6 = 0$ $x^3 - 2x^2 + 3x -6 = 0$ by grouping?

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Answer 1 · 2016-08-06T20:43:30

= $(x - 2) (x^{2} + 3)$ $(x-2)(x^2 +3)$

Explanation:

There are 4 terms, but there is no common factor in all of the terms.
Group them into pairs to create a common factor.
There must be a + sign between the pairs. This can be changed later if necessary.

$(x^{3} - 2 x^{2}) + (3 x - 6) = 0 look for common factors$ $(x^3 - 2x^2) + (3x -6) = 0" look for common factors"$

= $x^{2} (x - 2) + 3 (x - 2) there is a common bracket$ $x^2(x -2) +3(x-2) " there is a common bracket"$

= $(x - 2) (x^{2} + 3)$ $(x-2)(x^2 +3)$

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How do you factor $x^{3} - 2 x^{2} + 3 x - 6 = 0$ $x^3 - 2x^2 + 3x -6 = 0$ by grouping?

1 Answer

Explanation:

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How do you factor x3−2x2+3x−6=0x^3 - 2x^2 + 3x -6 = 0 by grouping?

1 Answer

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How do you factor $x^{3} - 2 x^{2} + 3 x - 6 = 0$ $x^3 - 2x^2 + 3x -6 = 0$ by grouping?