How do you factor $3 x^{2} + 8 x + 4$ $3x^2+8x+4$ by using the grouping method?

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Answer 1 · 2018-03-29T02:09:04

$(x + 2) (3 x + 2)$ $(x + 2)(3x + 2)$

1) Multiply the $a$ $a$ and $c$ $c$ terms together which in this case is $3$ $3$ and $4$ $4$ .

$3 \times 4 = 12$ $3 \times 4 = 12$

2) Find factors of $12$ $12$ that when added together will get you to the $b$ $b$ term, which is $8$ $8$ .

Those two are $2$ $2$ and $6$ $6$ .

3) Expand and factor with grouping. Closely follow the steps.

$3 x^{2} + 2 x + 6 x + 4$ $3x^2 + 2x + 6x + 4$

$x (3 x + 2)$ $x(3x + 2)$ and $2 (3 x + 2)$ $2(3x + 2)$

$(x + 2) (3 x + 2)$ $(x + 2)(3x + 2)$

How do you factor 3x2+8x+43x^2+8x+4 by using the grouping method?