How do you factor by grouping. $4+5xy-10y-2x$ ?

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Answer 1 · 2018-03-12T15:47:28

$(2-x)(2-5y)$

If you have four terms without a common factor you need to group them.

Grouping like this $(4+5xy)+(-10y-2x)$ achieves little.

Group the terms differently:

$(4-2x)+(5xy-10y)" "larr$ find the HCF of each bracket

$=2(2-x) color(blue)(+5y(x-2))" "larr$ divide $-1$ out as a factor

$=2(2-x)-5y(-x+2)" "larr$ the signs change

$2(2-x)-5y(2-x)" "larr$ makes equal brackets

$(2-x)(2-5y)" "larr$ there are two factor

OR:

$(4-10y) +(-2x+5xy)$

$=2(2-5y)+x(-2+5y)$

$=2(2-5y)-x(2-5y)$

$=(2-5y)(2-x)$

How do you factor by grouping. 4+5xy-10y-2x4+5xy-10y-2x?