How do you factor by grouping #2m^4 + 6 - am^4 - 3a#?

1 Answer
Alan P.
Jul 23, 2015

Extract factors from #2m^4+6# and #-am^4-3a# leaving a factor common to both; then extract that factor:
#color(white)("XXXX")##2m^4+6-am^4-3a = (2-a)(m^4+3)#

Explanation:

#2m^4+6 - am^4-3a#

#color(white)("XXXX")##= (color(red)(2m^4+6)) - (color(blue)(am^4+3a))#

#color(white)("XXXX")##=color(red)(2)(m^4+3) - color(blue)a(m^4+3)#

#color(white)("XXXX")##= (2-a)(m^4+3)#

Related questions
See all questions in Factoring by Grouping
Impact of this question
2028 views around the world
You can reuse this answer
Creative Commons License