How do you factor $12n^3+15n^2+4n+5$ ?

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Answer 1 · 2015-05-03T18:46:09

$12n^3+15n^2+4n+5$

By inspection the first two terms are $3n^2$ times the last two terms

$12n^3+15n^2+4n+5$
$=(3n^2)(4n+5) + (1)(4n+5)$

$=(3n^2+1)(4n+5)$

How do you factor 12n^3+15n^2+4n+512n^3+15n^2+4n+5?