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How do you express in terms of ln2 and ln3 given #ln 3 sqrt 2#?

1 Answer

May 4, 2016

#ln(3sqrt(2)) = ln(3) + 1/2ln(2)#

Explanation:

Using the properties that #ln(ab) = ln(a) + ln(b)# and #ln(a^x) = xln(a)#, we have:

#ln(3sqrt(2)) = ln(3)+ln(sqrt(2))#

#=ln(3) + ln(2^(1/2))#

#=ln(3) + 1/2ln(2)#

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