How do you expand #Ln (xyz^2)#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Gerardina C. Jan 8, 2017 #ln(xyz^2)=lnx+lny+2lnz# Explanation: Since #ln(ab)=lna+lnb#, you get: #ln(xyz^2)=lnx+lny+lnz^2#. Since #lna^b=blna#, you get: #ln(xyz^2)=lnx+lny+2lnz# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 3589 views around the world You can reuse this answer Creative Commons License