How do you evaluate the integral $int sintheta/(2-costheta)$ ?

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Answer 1 · 2017-03-22T23:18:38

$int (sinthetad theta)/(2-cos theta) = ln (2-costheta) + C$

Substitute:

$x = 2-costheta$

$dx = sintheta d theta$

and we have:

$int (sinthetad theta)/(2-cos theta) = int dx/x= ln abs x+C = ln (2-costheta) + C$

How do you evaluate the integral int sintheta/(2-costheta)int sintheta/(2-costheta)?